Also, what about this:

(loop [z (zip/seq-zip '((nil) 0))] 
  (if (zip/end? z) 
    :done 
    (do (println (zip/node z)) 
      (recur (zip/next z)))))

Which produces:

((nil) 0)
(nil)
nil
0
:done

On Saturday, December 21, 2013 5:59:16 PM UTC-5, Lee wrote:


> On Dec 21, 2013, at 11:49 AM, Lee Spector wrote: 
>
> > 
> > When I step through a zipper made from a nested list via seq-zip, I get 
> extraneous nils after processing a nested (). 
> > 
> > Is this somehow expected behavior, or a bug, or am I misunderstanding 
> something fundamental? 
> > 
> > The problem seems to arise only when an nested empty list is present, 
> not other nested lists and not other nested empty sequences (see example at 
> bottom for this bit). 
>
> I take it back about it working correctly with other nested empty 
> sequences. I realize now that my example of that had a nested empty vector, 
> not a sequence. Trying to reproduce that example with a nested empty 
> sequence just confused me, because it turns out that (seq ()) = (seq []) = 
> nil, and I'm not sure what that means... But this is all really a 
> distraction from the case I care about, which is lists that contain (among 
> other things) nested empty lists. For example, '(() 0). Here it seems to me 
> that zip/next's behavior is clearly wrong and I'm not sure why or what to 
> do about it. 
>
> Thanks, 
>
>  -Lee

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