If you want to be able to control an arbitrary long-running function, a
safe way is to run it in a separate process. That way you can safely
terminate it anytime you want. Of course this opens up a lot of other
issues .... :)


On Wed, Jan 22, 2014 at 9:15 PM, Mark Engelberg <[email protected]>wrote:

> I think the fib example is a good one in the sense that you are dealing
> with an already function that takes a long time, and isn't written as a
> loop.
>
> But in general, I want to solve the problem for an arbitrary long-running
> computation, for example, a call into a library that you don't control.
>
> One of the flagship examples for core.async is the example where you try
> two different engines to look something up, return the first one or
> timeout.  Similarly, I want to try to solve a computational problem two
> different ways, and take the first solution or timeout.  But of course,
> that only works if I can stop the computation from spinning CPU once I
> already have a solution (or timeout).
>
> Rewriting the underlying algorithms to constantly check for an interrupt
> is not an option.
>
>
>
>
> On Wed, Jan 22, 2014 at 11:31 AM, Praki Prakash 
> <[email protected]>wrote:
>
>> What is the task doing? If it is in a tight loop, it must check
>> explicitly whether the interrupt flag is set and abort. If it is waiting on
>> some resource, it will receive InterruptedException.
>>
>> Regards,
>> Praki Prakash
>>
>>
>> On Wed, Jan 22, 2014 at 11:20 AM, Mark Engelberg <
>> [email protected]> wrote:
>>
>>> On Wed, Jan 22, 2014 at 2:51 AM, Jozef Wagner <[email protected]>wrote:
>>>
>>>> You can put the computation into a future, and cancel the future after
>>>> the timeout.
>>>>
>>>
>>> I experimented with that, but it didn't seem to work.  I suspect that
>>> "canceling a future" doesn't really do what I think it should do.  I would
>>> appreciate some further clarity on how future cancellations work, and if
>>> someone thinks it applies here, would like to see concretely how to do it.
>>>
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