The key thing to remember in all questions of core.async GC is that there
is no global "blocked gos" queue. Instead, the blocked "gos" are attached
directly to the channel. When the channel is GC'd all attached gos are GC'd
as well.

So in this case, it's actually even simpler.....the go never blocks. What
this code is doing is creating a channel to return from the go. This
channel has a buffer size of 1. It then puts a channel into the channel.
The go then exits and is GC'd. Once the return channel is discarded by the
caller of this code, both channels are also GC'd

Timothy


On Thu, Jan 30, 2014 at 11:24 AM, t x <txrev...@gmail.com> wrote:

> Hi,
>
>   Consider this block of code:
>
>   (async/go (async/chan))
>
>   This creates a go-thread and a go-chan.
>
>   The go-thread is linked from the list of blocked go-threads.
>
>   The go-chan is linked from the go-thread.
>
>   Thus, did we just create a go-thread and a go-chan which is NOT gc-ed at
> all?
>
> Thanks!
>
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-- 
"One of the main causes of the fall of the Roman Empire was that-lacking
zero-they had no way to indicate successful termination of their C
programs."
(Robert Firth)

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