So you DON'T mean: (juxt quot rem)
?
Anthony Ortiz <mailto:anthonypa...@gmail.com> April 9, 2014 11:01 AM Hello everyone, I am able to get the quotient or remainder by doing the following : (quot 22 7) -> 3 (rem 22 7) -> 1Is there a way to get back both the quotient and the remainder in one calculation rather than performing two separate calculations? And I don't mean writing a function that does both calculations behind the scenes and returning a list of both results.Cheers! Anthony -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.comNote that posts from new members are moderated - please be patient with your first post.To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en ---You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com <mailto:clojure+unsubscr...@googlegroups.com>.For more options, visit https://groups.google.com/d/optout.
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