Hello,
Im now at the last exercise of the beginners exercise of 4clojure.
I figured out that this solution works.
(fn [default lijst1]
(loop [lijst lijst1 d {}]
(if (empty? lijst)
d
(recur (rest lijst) (assoc d (first lijst) default)))))
But as I see it lijst lijst 1 and d are all the same. They all contains the
collection which has to fill in the end collection.
As a example I mean default = 0 lijst 1 [:a :b: :c]
then lijst1 and d also contains [:a :b:c] so what is then the point of
using 3 arguments.
Roelof
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