I picked a toy problem that was really easy to solve, figuring that once I
had the idea down, I would be able to easily change the equation to the one
that I am interested in solving. In moving to my real problem I hit the
next snag I can't use real numbers within the equation. I note that the
equation hasn't changed, the values of x and y are still non-negative
integers.
(run* [q]
(fresh [x y]
(fd/in x y (fd/interval 0 9))
(fd/eq
(= (+ (* x 3.) (* y 2.)) 8.))
(== q [x y])))
In my real problem I expect that I could have something like
(run* [q]
(fresh [x y]
(fd/in x y (fd/interval 0 9))
(fd/eq
(= (+ (* x 3.1111) (* y 2.2222)) 8.4444))
(== q [x y])))
Is there away to do this?
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