Ah sorry I miss read. Not currently supported, it's a requested
feature from Prolog that I haven't gotten around to implementing.

David

On Thu, Nov 13, 2014 at 12:53 PM, Daniel Stone <dan.stone16...@gmail.com> wrote:
> I'm not sure I fully understand, I guess I'm looking for the equivalent to a
> sub query? When I tried to implement this early, I naively perhaps tried
> something like this:
>
> (defn bars-for-foo
>   [?foo ?bars]
>   (l/== ?bars
>     (l/run* [?q]
>       (fooz ?foo ?q))))
>
> This seems relevant: http://dev.clojure.org/jira/browse/LOGIC-68
>
>
>
> On Thu, Nov 13, 2014 at 5:28 PM, David Nolen <dnolen.li...@gmail.com> wrote:
>>
>> There's no need to define the reverse relation - fooz can do it. Just
>> supply bar and leave the foo fresh.
>>
>> David
>>
>> On Thu, Nov 13, 2014 at 12:26 PM,  <dan.stone16...@gmail.com> wrote:
>> > I think this is a dummy question, but wondering whether this is possible
>> > in
>> > core.logic?
>> >
>> > Lets say I have a set of relations
>> >
>> > (db-rel foo p)
>> > (db-rel bar p)
>> > (db-rel fooz p p2)
>> >
>> > and facts
>> > [foo 1]
>> >
>> > [bar 2]
>> > [fooz 2 1]
>> >
>> > [bar 3]
>> > [fooz 3 1]
>> >
>> > See that the fooz relation is potentially describing bar as children of
>> > foo's. (like a foreign key)
>> >
>> > and I want to unify with all the `bar`s for a given `foo` like so:
>> >
>> > (run* [?q]
>> >  (fresh [?foo ?bars]
>> >   (bars-for-foo ?foo ?bars)
>> >   (l/== {:foo ?foo
>> >            :bars ?bars}
>> >           ?q)))
>> > =>
>> >
>> > ({:foo 1, :bar (2 3)})
>> >
>> > Is it possible to define bars-for-foo?
>> >
>> >
>> >
>> >
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