Hey Mayank!

Similarly to your attempt last time, you need to use gen/bind to get the
result of a generator which you can then use to make a new generator.

(defn- rand-interleave* [coll acc]
  (if (seq coll)
    (gen/bind (gen/choose 0 (dec (count coll)))
              (fn [index]
                (let [value (first (get coll index))
                      coll (->> (update-in coll [index] next)
                                (remove empty?)
                                vec)]
                  (rand-interleave* coll (conj acc value)))))
    (gen/return acc)))

(defn rand-interleave [& colls]
  (rand-interleave* (vec colls) []))

The (gen/choose 0 (dec (count coll))) is similar to your rand-count
function, then the generated number is passed to the function as result.
Writing it this way will shrink towards the (apply concat args) (ie. as it
shrinks it will move towards just concatenating the arguments).

In terms of the recursion: this will eventually overflow the stack. I don't
know of a way to trampoline generators, so I don't know how to avoid that.
(This is a bit of a recurring problem with monadic code in Clojure, I feel,
as algo.monads had a similar problem last time I checked.) For the moment
I'm just ignoring this theoretical problem until it becomes a practical
problem.

I hope that helps!

Carlo

On 14 August 2015 at 23:39, Mayank Jain <firesof...@gmail.com> wrote:

> Hi Everyone,
>
> Here's the problem I am facing,
> I need to write a generator which takes any number of sequences,
> interleaves them but maintains the order within each sequence.
> Assume each sequence has at least one element.
>
> For example:
>
> (rand-interleave [1 2 3 4] [:a :b] [:A :B :C :D :E])
>> => [:a 1 2 :b :A :B :C 3 :D 4 :E]
>
>
> (rand-interleave [1 2 3 4])
>> => [1 2 3 4]
>
>
> (rand-interleave [1])
>> => [1]
>
>
> (rand-interleave [1] [:a] [:A])
>> => [:a 1 :A]
>
>
> I have been able to write this down as clojure functions.
> But I am unable to convert this into a test.check generator.
>
> Specifically:
>
>    - How to pass random index count without using rand-int i.e. use
>    gen/choose
>    - How do I write recursive functions which play well with test.check
>
> Here's my take on it (without the generators).
>
> (defn- first-nth
>>   "(first-nth [[1 2 3 4] [:a :b :c :d]]
>>                   1)
>>    => :a"
>>   [coll n]
>>   (first (nth coll n)))
>
>
>
> (defn- next-nth
>>   "(next-nth [[1 2 3 4] [:a :b :c :d]]
>>                   1)
>>    => [[1 2 3 4] (:b :c :d)]"
>>   [coll n]
>>   (->> n
>>        (nth coll)
>>        next
>>        (assoc coll n)
>>        (remove nil?)
>>        vec))
>
>
>
> (defn- rand-count
>>   [coll]
>>   (rand-int (count coll)))
>
>
>
> (defn- rand-interleave*
>>   [coll acc]
>>   (let [n (rand-count coll)]
>>     (if (not-empty coll)
>>       (rand-interleave* (next-nth coll n)
>>                                   (conj acc
>>                                           (first-nth coll n)))
>>       acc)))
>
>
>
> (defn rand-interleave
>>   [& args]
>>   ;; Make args a vector as I would like to
>>   ;; look up elements by their index values.
>>   (rand-interleave* (vec args) []))
>
>
> Looking forward to any suggestions on how to solve it :)
>
> Thanks,
> Mayank.
>
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