Thanks Mark. That is exactly what I ended up doing.

Regards,
Sunil.

On Sun, Dec 13, 2015 at 8:45 PM, Mark Engelberg <mark.engelb...@gmail.com>
wrote:

> Call your memoized function on values 1 .. n-1 first, before calling it on
> n.
> On Dec 12, 2015 9:45 PM, "Sunil S Nandihalli" <sunil.nandiha...@gmail.com>
> wrote:
>
>> a small correction. The function computes the modulo 100000007 of the
>> answer and not the answer itself. I ran it in the repl.
>> Thanks,
>> Sunil.
>>
>> On Sun, Dec 13, 2015 at 11:08 AM, Sunil S Nandihalli <
>> sunil.nandiha...@gmail.com> wrote:
>>
>>> Hi Everybody,
>>> I wrote the simple function for computing the number of
>>> binary-search-trees that can be formed from a sequence of numbers from 1 to
>>> N using memoization. I get a stack-overflow for values more than N of 196.
>>> Can anybody help me in figuring out how to fix this?
>>> Thanks,
>>> Sunil.
>>>
>>> (defn num-trees [n]
>>>   (let [modulo 100000007
>>>         trunc #(mod % modulo)
>>>         mult-m (comp trunc *)
>>>         add-m (comp trunc +)
>>>         h (fn [mf l]
>>>             (if (<= l 1) 1
>>>                 (trunc (reduce add-m 0
>>>                                (map #(mult-m (mf mf (- l % 1)) (mf mf %))
>>>                                     (range l))))))
>>>         mf (memoize h)]
>>>     (mf mf n)))
>>>
>>>
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