Thanks for answer my question.

On Saturday, December 26, 2015 at 10:59:51 PM UTC+8, Leif wrote:
>
> Hi, Mian Pao.
>
> When you call the macro te, a is bound to the *symbol* 'print, not the 
> *function* print.  So, what the ~(a b c) form is doing is calling the 
> symbol 'print as a function:
> ('print 1 '(2 3)) => '(2 3)
>
> This is because symbols and keywords implement the function interface, and 
> the call above is equivalent to 
> (get 1 'print '(2 3)) => '(2 3) ; Tries to look up 'print in the data 
> structure 1, fails, uses default value '(2 3).
>
> Hope that helps,
> Leif
>
> On Thursday, December 24, 2015 at 8:38:44 AM UTC-5, Mian Pao wrote:
>>
>> I just write a macro
>>
>> ```
>> (defmacro te
>>   [a b & c]
>>   `(print
>>      ~(a b c)))
>> ```
>>
>> and i run
>>
>> ```
>> (macroexpand '(te print 2 3 4))
>> ;=> (clojure.core/print (3 4))
>> ```
>>
>> it get `(clojure.core/print (3 4))` not `(clojure.core/print nil)`
>>
>> iti is mean `(print 2 '(3 4))` return (3 4)?
>>
>

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