Is there a special check when the equality is asked on map ?

I thought the evaluator evaluate all the expression the same way , by 
substituting each expression contained in the list to other evaluators.

In the book, the author tells the substitution rule for function evaluation 
is responsible for no distinction between pointer equality and content 
equality. I can't understand this sentence.

Thank you for your answer though

Le samedi 17 décembre 2016 15:48:58 UTC-5, Alex Miller a écrit :
>
> Map equality is checked by verifying that the two maps have the same set 
> of keys and that each key is mapped to = values.

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