If anyone has a clue how to use it, I'd be grateful. This was my
unsuccessful attempt:
NSExpression * ex = [NSExpression expressionForFunction:[NSExpression
expressionForConstantValue:@"BAR"] selectorName:@"length"
arguments:nil];
NSPredicate * predicate = [NSCompoundPredicate
andPredicateWithSubpredicates:[NSArray arrayWithObject: ex]];
[predicate evaluateWithObject:@"FOO" substitutionVariables:nil];
[NSFunctionExpression evaluateWithObject:substitutionVariables:]:
unrecognized selector sent to instance 0x68b8af0
On 29/06/2008, at 12:43 AM, Shawn Erickson wrote:
On Jun 28, 2008, at 12:13 AM, Chris <[EMAIL PROTECTED]> wrote:
NSExpression defines this method:
+ (NSExpression *)expressionForFunction:(NSString *)name arguments:
(NSArray *)parameters
and the doco provides this example:
[NSExpression expressionForFunction:(@selector(random))
arguments:nil];
Isn't that wrong? Can you really pass a selector to a NSString
argument? The compiler is complaining, and the program crashes when
I attempt.
Yeah it is wrong. I believe you just pass a string with the same
contents as what you would put in @selector.
-shawn
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