That is *extremely* clear - thanks! m.

On Jun 29, 2013, at 9:42 AM, Jens Alfke <j...@mooseyard.com> wrote:

> 
> On Jun 29, 2013, at 9:20 AM, Matt Neuburg <m...@tidbits.com> wrote:
> 
>> I'm trying to come up with a pithy explanation, suitable for beginners, of 
>> why a "static" variable doesn't need a "__block" specifier in order for a 
>> block to assign to it. The word "captured", as you suggest, may be useful 
>> here, since this embodies the notion that an automatic variable is copied as 
>> const (and so can't be assigned to) in the context of the block. Thx - m.
> 
> The block is going to run in its own stack frame, like a regular function. 
> But there’s no normal way for a function to access a local variable of 
> another function (the enclosing function of the block.) So enclosing 
> variables used by the block either have to be copied in the block’s stack 
> frame, or referenced through pointers back to the enclosing stack frame. The 
> latter is clearly more expensive, both because of the pointer dereference and 
> because there’s extra work that has to be done to rescue that variable if the 
> block can survive past the return of its caller (because the stack frame will 
> be gone later on.) That’s why it’s optional, and you have to use __block to 
> get that behavior.
> 
> None of this is an issue with a static or global variable because it doesn’t 
> live on the stack or belong to some enclosing function. It’s just got a 
> single location that’s valid for the lifetime of the program. (Even if you 
> declared it inside a function: that only affects where the variable can be 
> referred to, not its lifetime.)
> 
> —Jens

--
matt neuburg, phd = m...@tidbits.com, http://www.apeth.net/matt/
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