Hi all, is there a way to jump across the following
problem?
1)
<xsp:logic>
if(viewer.isPie()){ <tr><td bgcolor="#ffffff" width="340" height="20" vlign="bottom" align = "left" colspan = "2"> <img><xsl:attribute name = "src"> <xsl:value-of select="../report_information/piechart/@path"/><xsp:expr>viewer.getUnavailable()</xsp:expr> </xsl:attribute></img> </td></tr> } </xsp:logic> 2) Alternatively, I try to
define a xsl variable and assign it with in
<xsl:variable name = "param"
><xsp:expr>viewer.getUnavailable()</xsp:expr></xsl:variable> <xsp:logic> if(viewer.isPie()){ <tr><td bgcolor="#ffffff" width="340" height="20" vlign="bottom" align = "left" colspan = "2"> <img><xsl:attribute name = "src"> <xsl:value-of select="../report_information/piechart/@path"/><xsl:value-of select="{$param}"> </xsl:attribute></img> </td></tr> } </xsp:logic> but it return the variable's name end not its
value.
Thank all in advance Simone.
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- Re: Can not add xsp:expr to xsl:attribute Simone Bortolaso