Try this. See util.xsl and XSPUtil.java for the sources.
Thanks,
dims
InputSource is = new InputSource(
new FileReader(
XSPUtil.relativeFilename(
"votes.xml",
objectModel
)
)
);
--- Yasir Khalil Al Masri <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I'm tring in one of the XSP pages to call an XML file that resides on
> my machine. It came to me that as you can call an image by mapping it
> through:
> <map:match pattern="images/**.png">
> <map:read src="project/images/{1}.png" mime-type="image/png"/>
> </map:match>
>
> you can do the same for the XML files:
> <map:match pattern="**.xml">
> <map:read src="project/XMLfiles/{1}.xml" mime-type="text/xml"/>
> </map:match>
>
> Now in one of the XSP files, I'm doing this:
> InputSource input = new InputSource( new FileInputStream(
> "votes.xml" ) );
> where votes.xml is in the XMLfiles directory. I suppose that mapping
> like this is clear enough to tell the cocoon engine where to find this
> file, but whenever I execute this code I got a large stack dumped to
> the server monitor saying that it cannot find the file mentioned. I
> tried to put it in many shapes like:
> InputSource input = new InputSource( new FileInputStream(
> "cocoon:/XMLfiles/votes.xml" ) );
>
> Even I tried to call it directly from the current working directory, or
> from the root of the project without mapping, I always got the same
> result.
>
> I succeeded only when I hardcoded the full path of the file starting
> from the current drive, which I don't think it's a professional way to
> do this.
>
> Do anybody have comment on this?
>
> Thanx.
>
>
>
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=====
Davanum Srinivas, JNI-FAQ Manager
http://www.jGuru.com/faq/JNI
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