Hello cocoon-users,
I have a easy problem...! I want to make a link with parameter in
the url. I read some data from a database (user with diffrent
usernames). Now I want to make links to a other xsp page and the
username should be in the query. e.g.
http://localhost:8080/cocoon/showuser?username=testuser
I have a xsp page and I list all users with a xsl file...all work
fine, but with no link...how can I implement a link. I tried id to
implement it in the xsl file.
here I print out the username, name and firstname:
the problem ist the href section!
<xsl:template match="result-attr">
<tr>
<td align="left">
<a href="">
<xsl:value-of select="result-id"/>
</a>
</td>
<td align="left">
<xsl:value-of select="result-name"/>
</td>
<td align="left">
<xsl:value-of select="result-firstname"/>
</td>
</tr>
</xsl:template>
--
Best regards,
rgi mailto:[EMAIL PROTECTED]
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