ok, now I have taken the original sitemap file given with Cocoon,
I have substituted the original map:pipeline with this:
<map:pipeline>
<map:match pattern="">
<map:redirect-to uri="myAppplication/myfile.html"/>
<map:match>
<map:match pattern="myApplication/*.html">
<map:generate src="myApplication/{1}.html"/>
<map:serialize type="html"/>
</map:pipeline>
I have restarted tomcat and ....
the same "error" is returned:
*************
Apache Tomcat/4.0.1 - HTTP Status 404 - Not Found
----------------------------------------------------------------------------
----
type Status report
message Not Found
description The requested resource (Not Found) is not available.
**************
Thanks for your help.
----- Original Message -----
From: "Bertrand Delacretaz" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, March 04, 2002 4:10 PM
Subject: Re: Sitemap question
> On Monday 04 March 2002 15:55, Stefano Bonnin wrote:
> > How can I define a very simple pipeline that gets the initial URI and
> > present a simple HTML file?
> . . .
> > <map:pipeline>
> > <map:match pattern="">
> > <map:redirect-to uri="myApplication/myfile.html"/>
> > </map:match>
> > </map:pipeline>
>
> That's only the beginning, it will redirect the / URL to
> myApplication/myfile.html.
>
> Then, the redirect causes the client (browser) to make another request
> to myApplication/myfile.html, which your sitemap must process.
>
> Here's one way of doing it:
>
> <map:match pattern="myApplication/*.html">
> <map:generate src="myApplication/{1}.html"/>
> <map:serialize type="html"/>
> </map:match>
>
> Hope this helps!
>
> --
> Bertrand Delacrétaz (codeconsult.ch, jfor.org)
>
> buzzwords: XML, java, XSLT, cocoon, mentoring/teaching/coding.
> disclaimer: eternity is very long. mostly towards the end. get ready.
>
>
>
>
>
>
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>
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