Hi,
To copy all types of all level sub-nodes you can use copy-of tag:
<xsl:copy-of select="some_element"/>
In this case you need not special template with for-each processing.
Best regards.
Roman
"Hahn Kurt (CHA)" wrote:
> Actually, the problem was something else, somebody else just pointed me to
> check for different namespaces, and that solved the problem, I needed to
> reference the elements with their corresponding NS.
>
> Thanks
>
> -----Message d'origine-----
> De: TREGAN Fabien [mailto:[EMAIL PROTECTED]]
> Date: jeudi, 28. mars 2002 10:45
> À: '[EMAIL PROTECTED]'
> Objet: RE: Simple XSL problem, but NEED HELP!
>
> >-----Message d'origine-----
> >De: Andreas Hartmann [mailto:[EMAIL PROTECTED]]
>
> >Hi,
>
> </>
>
> >At least in your example the <row> tag has no value, so it is
> >absolutely correct that nothing is returned. If you use <xsl:value-of>,
> >you will only get the value of the matched tag.
> >
>
> If you want a copy of all the tag, us xsl:copy.
>
> If you need to copy all the tag, attributs, and inner tag, you can use
> recursive-copy by using a named template and applying your template to the
> node to be copyed.
>
> I think that the template should look like :
>
> <xsl:template name="copyall">
> <xsl:copy>
> <xsl:for-each select="@*|node()">
> <xsl:call-templates name="copyall"/>
> </xsl:copy>
> </xsl:template>
>
> hope this works, i've not practiced for a long time :)
>
> >
> >Greetings,
> >Andreas
>
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