I've been trying to get the form validator and DB Validator working for about a week now. I decided to try and just got the form stuff working first but I can't even get that. I'm running Cocoon 2.0.2-dev and Tomcat 4.1.3.
In my sitemap.xmap I have the following: <!-- | The page do_login does not actually exist this is just a dummy | target for the login auth to take place at. --> <map:match pattern="do_login.xsp"> <map:act type="form-validator"> <map:parameter name="descriptor" value="context://house_bills/descriptors/params.xml"/> <map:parameter name="validate-set" value="user-pass"/> <map:redirect-to uri="index.xsp"/> </map:act> <map:redirect-to uri="login.xsp"/> </map:match> login.xsp has a form that posts to do_login.xsp and has two inputs named user_name and user_password. Here is my params.xml <?xml version="1.0"?> <root> <parameter name="user_name" type="string" nullable="no"/> <parameter name="user_password" type="string" nullable="no"/> <constraint-set name="name-pass"> <validate name="user_name"/> <validate name="user_password"/> </constraint-set> </root> I've checked through the logs and there aren't any context errors so Cocoon seems to be finding the params.xml file OK. Everytime I submit the form I get bounced back to the login.xsp page instead of getting sent to index.xsp. It doesn't matter if I don't put anything in the inputs or have valid data in both. I would also like to be able to validate the user_name & password_fields against a MySQL database and setting the value in the corresponding user_id column in a session variable. I played with it a little and cocoon was connection to the DB but not authenticating, I don't have my descriptor file for that any more. Here is my DDL for the table I want to auth against. CREATE TABLE `users` ( `user_id` int(11) unsigned NOT NULL auto_increment, `user_name` varchar(255) NOT NULL default '', `user_password` varchar(16) NOT NULL default '', `user_first_name` varchar(255) NOT NULL default '', `user_last_name` varchar(255) NOT NULL default '', `user_email` varchar(255) NOT NULL default '', `user_status` tinyint(4) unsigned NOT NULL default '1', PRIMARY KEY (`user_id`), UNIQUE KEY `user_login` (`user_name`,`user_password`), UNIQUE KEY `user_id` (`user_id`) ) TYPE=MyISAM My other question with the DBAuth stuff is can cocoon run the submitted password through MySQLs PASSWORD() function? I would really like to be able to keep the password column in the table encrypted and still be able to use the DBAuth stuff. I hope someone can give me a hand with this. After a week of searching the mailing lists, coocon site and web in general I'm stuck! -Eric Dalquist --------------------------------------------------------------------- Please check that your question has not already been answered in the FAQ before posting. <http://xml.apache.org/cocoon/faq/index.html> To unsubscribe, e-mail: <[EMAIL PROTECTED]> For additional commands, e-mail: <[EMAIL PROTECTED]>