Re: i18n question

[Ivan Luzyanin]

On Wednesday 18 September 2002 17:09, Mathias Ochsendorf wrote:
> > <a href="/test">
> >    <img>
> >     <xsl:attribute name="src">
> >             <i18n:translate>
> >                     
><i18n:text>/images/test.svg?label_text={0}&amp;label_color={1}</i18n:t
> >ext> <i18n:param><i18n:text>hello</i18n:text></i18n:param>
> >                     <i18n:param><i18n:text>red</i18n:text></i18n:param>
> >             </i18n:translate>
> >     </xsl:attribute>
> >    </img>
> > </a>
>
> unfortunately this approach doesn't work. it causes a
> nullpointerexception:
>
> Original exception :
> org.apache.avalon.excalibur.xml.xslt.XSLTProcessorException: Exception in
> creating Transform Handler
> at
> org.apache.avalon.excalibur.xml.xslt.XSLTProcessorImpl.getTransformerHandle
>rAndValidity(XSLTProcessorImpl.java:287) at
> org.apache.cocoon.transformation.TraxTransformer.setup(TraxTransformer.java
>:333)

Sure it will couse a nullpointerexception. First of all you need to to get 
from this snip something like this:

<a href="/test">
    <img>
        <xsl:attribute name="src">
                        /images/test.svg?label_text=hello&amp;label_color=red
        </xsl:attribute>
    </img>
 </a>

and than use this stylesheet

See example:

Your sitemap should have:

<map:match pattern="stylesheets/*.xsl">
        <map:generate src="stylesheets/{1}.xsl"/>
        <map:transform type="i18n"/> <!-- will generate a valid xsl without i18n 
tags, and it will not couse an error anymore -->
        <map:serialize type="xml"/>
</map:match>

<map:match pattern="...">
        <map:generate src="<you-source>"/>
        <map:transform src="cocoon:/stylesheets/<stylesheet-with-my-snip>.xsl"/> <!-- 
use stylesheet generated by previous pipeline -->
        <map:serialize/>
</map:match>

Regards!
Ivan Luzyanin.

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