Yep, that works. Thanks for your help. Best Regards, J
-----Original Message----- From: Scott Warren [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 23, 2003 4:33 PM To: [EMAIL PROTECTED] Subject: Re: XSP All Nodes Even No not a second stylesheet, Change your stylesheet to be like this <xsl:template match="table"> <xsl:for-each select="tr"> <xsl:if test="position() mod 2 = 0"> <tr class="evenrow"><xsl:apply-templates/></tr> </xsl:if> <xsl:if test="position() mod 2 = 1"> <tr class="oddrow"><xsl:apply-templates/></tr> </xsl:if> </xsl:for-each> </xsl:template> Where table is assumed to be the parent node of all the tr nodes. Does this help ? Scott Warren Jacob Arnold wrote: If my query returns 56 records (1 per row) then I get 2, 4, 6, 8, 10... through 114. Are you suggesting adding a second stylesheet? Thanks, J -----Original Message----- From: Scott Warren [mailto:[EMAIL PROTECTED]] Sent: Thursday, January 23, 2003 4:22 PM To: [EMAIL PROTECTED] Subject: Re: XSP All Nodes Even What is the value that position() is returning? Can you move the template into a another template that has a <xsl:for-each select="tr"> I think you may get different results then. Hope this helps Scott Warren Jacob Arnold wrote: Whenever I test for even nodes using XSLT on my serialized XSP, all the nodes are even. For example, I'm trying to make every even table row a different color: <xsl:template match="tr"> <xsl:if test="position() mod 2 = 0"> <tr class="evenrow"><xsl:apply-templates/></tr> </xsl:if> <xsl:if test="position() mod 2 = 1"> <tr class="oddrow"><xsl:apply-templates/></tr> </xsl:if> </xsl:template> But every table row is getting the evenrow class applied. When I display the position, every row (and every <td> for that matter) is even-numbered. Does anyone know what might be causing this? Here's a sitemap fragment: <map:match pattern="**.xsp"> <map:act type="resource-exists"> <map:parameter name="url" value="docs/{1}.xsp"/> <map:generate src="docs/{../1}.xsp" type="serverpages"/> <map:serialize/> </map:act> <map:generate src="docs/404.xsp"/> <map:transform src="stylesheets/encode-html.xsl"/> <map:serialize/> </map:match> <map:match pattern="**.html"> <map:aggregate element="document"> <map:part src="cocoon:/menu.xsp" strip-root="true"/> <map:part src="cocoon:/{1}.xsp" strip-root="true"/> </map:aggregate> <map:transform src="stylesheets/encode-html.xsl"/> <map:serialize/> </map:match> I'm using Cocoon 2.0.4 on Tomcat 4.1.12. Thanks, J --------------------------------------------------------------------- Please check that your question has not already been answered in the FAQ before posting. <http://xml.apache.org/cocoon/faq/index.html> To unsubscribe, e-mail: <[EMAIL PROTECTED]> For additional commands, e-mail: <[EMAIL PROTECTED]>
