On Wed, Jun 14, 2006 at 12:22:09AM +1000, Benno wrote:
>
> And now for the C version
>
Here's a C++/boost version:
#include <iostream>
#include <cmath>
#include <boost/lexical_cast.hpp>
using namespace std;
int
main(int argc, char **argv)
{
float amount = boost::lexical_cast<float>(argv[1]);
float remainder = fmodf(amount, 5.0);
float base_amount = amount - remainder;
float x;
if (remainder > 2) {
x = 5;
} else {
x = 0;
}
cout << base_amount + x << endl;
return 0;
}
Notes:
1. easy to write as I just made small changes to Benno's C version :-)
2. only interesting things over C is the boost::lexical_cast
and perhaps the cout line. lexical_cast will throw an exception and
print out an ugly error should you dare to supply it with non-numeric.
3. noticeably less clean than ruby or python
4. would take someone a fair bit of googling/experience to even
know about boost lexical_cast!
5. doesn't need stdlib as it doesn't use atof
6. binary about twice as big as the C version's
7. didn't demand to be linked with the maths library (-lm); I don't know why!
8. doesn't segfault if not given enough args (I know this wasn't in the spec
tho')
Of course, the C version is also a C++ version; you don't
have to use boost, iostreams....
Regards,
Matt
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