Author: humbedooh
Date: Tue Dec  8 11:08:48 2015
New Revision: 1718563

URL: http://svn.apache.org/viewvc?rev=1718563&view=rev
Log:
Add D'Hondt example

Modified:
    steve/site/trunk/content/vote_types.html

Modified: steve/site/trunk/content/vote_types.html
URL: 
http://svn.apache.org/viewvc/steve/site/trunk/content/vote_types.html?rev=1718563&r1=1718562&r2=1718563&view=diff
==============================================================================
--- steve/site/trunk/content/vote_types.html (original)
+++ steve/site/trunk/content/vote_types.html Tue Dec  8 11:08:48 2015
@@ -16,4 +16,18 @@
     For calculating result, we use Meek's Method with a quota derived from the 
Droop Quota but with implementation changes such as those proposed by New 
Zealand. 
        See <a 
href="http://svn.apache.org/repos/asf/steve/trunk/stv_background/meekm.pdf";>this
 paper</a> for details.
 
+       <h2 id="dh">D'Hondt (Jefferson) Voting</h2>
+<p>The D'Hondt method, also known as the Jefferson method, is a <i>highest 
average</i> method for calculating proportional representation of parties at an 
election.
+       In essence, this is done by calculating a quotient per party for each 
number of seats available and finding the highest values. The quotient is 
determined as 
+       <kbd>V/(s+1)</kbd> where <kbd>V</kbd> is the number of votes received 
and <kbd>s</kbd> is the number of seats won. Thus, for each party, the quotient 
is calculated 
+       for the number of seats available:
+</p>
+       <h4>Example result for election with 4 seats:</h4>
+       <table>
+               <tr><th>Party:</th><th>Votes:</th><th>1 seat:</th><th>2 
seats:</th><th>3 seats:</th><th>4 seats:</th><th>seats won:</th></tr>
+               <tr><td>Gnomes</td><td>25,000</td><td>25,000/(0+1) = 
<b>25,000</b></td><td>25,000/(1+1) = <b>12,500</b></td><td>25,000/(2+1) = 
8,333</td><td>25,000/(3+1) = 6,250</td><td>2</td></tr>
+               <tr><td>Elves</td><td>15,000</td><td>15,000/(0+1) = 
<b>15,000</b></td><td>15,000/(1+1) = 7,500</td><td>15,000/(2+1) = 
5,000</td><td>15,000/(3+1) = 3,750</td><td>1</td></tr>
+               <tr><td>Dwarves</td><td>10,000</td><td>10,000/(0+1) = 
<b>10,000</b></td><td>10,000/(1+1) = 5,000</td><td>10,000/(2+1) = 
3,333</td><td>10,000/(3+1) = 2,500</td><td>1</td></tr>
+       </table>
+       
 {% endblock %}


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