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Igor Vaynberg commented on WICKET-1041: --------------------------------------- because this is ajax, not a regular request. if you do not implement onerror() and you have a form validation error the user will not see any feedback. > Fix a TODO for 1.3 at AjaxFormSubmitBehavior.onError() > ------------------------------------------------------ > > Key: WICKET-1041 > URL: https://issues.apache.org/jira/browse/WICKET-1041 > Project: Wicket > Issue Type: Improvement > Components: wicket > Affects Versions: 1.3.0-beta3 > Reporter: Martin Grigorov > Assignee: Igor Vaynberg > Priority: Trivial > Fix For: 1.3.0-beta4 > > > There is the following TODO at > org/apache/wicket/ajax/form/AjaxFormSubmitBehavior.onError(): > /** > * Listener method invoked when the form has been processed and errors > occured > * > * @param target > * > * TODO 1.3: make abstract to be consistent with onsubmit() > * > */ > protected void onError(AjaxRequestTarget target) > { > } > Should this be done for 1.3 or it will stay like it is now for the next major > release ? -- This message is automatically generated by JIRA. - You can reply to this email to add a comment to the issue online.