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https://issues.apache.org/jira/browse/WICKET-1855?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Igor Vaynberg resolved WICKET-1855.
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Resolution: Fixed
Fix Version/s: 1.4-RC2
1.3.6
Assignee: Igor Vaynberg
> Using an AjaxSubmitLink outside of a Form does not set the form property
> ------------------------------------------------------------------------
>
> Key: WICKET-1855
> URL: https://issues.apache.org/jira/browse/WICKET-1855
> Project: Wicket
> Issue Type: Bug
> Components: wicket
> Affects Versions: 1.3.4
> Reporter: Pieter van Prooijen
> Assignee: Igor Vaynberg
> Priority: Minor
> Fix For: 1.3.6, 1.4-RC2
>
>
> When constructing an AjaxSubmitLink outside of a form using the constructor:
> public AjaxSubmitLink(String id, final Form form)
> The form argument is not set in the link. This prevents the form from seeing
> the link as its submitting component, which in turn means that using thing
> like enableDefaultFormProcessing() on the link don't work.
> Changing the constructor of AjaxSubmitLink to:
> public AjaxSubmitLink(String id, final Form form)
> {
> super(id, form) /* was: super(id) */
> ...
> }
> will probably fix the problem.
> A temporary workaround is to implement a getForm() method in the subclass of
> the submit link which answers the form of the link
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