Take a look at the FileUpload user guide: http://jakarta.apache.org/commons/fileupload/using.html
and you'll see that all of the items - file items and non-file items - are returned in the list from parseRequest(). You distinguish between file items and non-file items using the isFormField() method. -- Martin Cooper On 5/6/05, Mihael Knezevic <[EMAIL PROTECTED]> wrote: > hi, > > i got the uploading of a file running but now i want to pass some parameter > with it. what do i need to put in the html form and how do i get it from the > request object? > > my html form: > > <form ENCTYPE='multipart/form-data' method='POST' frm='frmUploadCatalog' > action='CatalogManagement'> > <input type='hidden' name='action' value='uploadCatalog'> > > <div align='center'><h4>Katalog hochladen</h4></div> > > Wählen Sie einen Katalog aus: <input type='file' name='catalog'> > > <br><br> > > <input type='radio' name='type' value='file' checked> als einzelne Datei > > <br> > > <input type='radio' name='type' value='jar'> als Archivdatei (mehrere > Dateien) > > <br><br> > > <input type='submit' name='absenden' value='hochladen'> > > </form> > > i like to get the value of the input field with the name type (radio buttons) > but don't know how. > > thanx in advance. > > mk > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
