Am 02.03.2009 14:18, Alan Bateman schrieb:
Ulf Zibis wrote:
Sherman, yes, you are right. That's not what I'm looking for.
This would be slower, than reading the stream directly, because the
underlying byte array will be copied 2 times by
BufferedInputStream#<init> + Channels.ReadableByteChannelImpl#read(),
... but maybe not, because looping BufferedInputStream#readChar()
could be slower than twice System.arraycopy().
Anyway, I'm looking for a DirectBuffer directly from a resource file.
So I think there is something missing:
URL.openChannel() or Class#getResourceAsChannel()
Maybe there is a way to get a RamdomAccessFile from URL to get the
Channel from. Anybody knows ?
A URL just identifies an abstract resource so it may not support
random access or other file-like operations you require. Have you
thought about special handling for when the scheme is "file"? That way
you can get the FileChannel you want for the typical case.
-Alan
I thought about something like:
FileChannel fc = new
RandomAccessFile(getClass().getResource(name).toURI().getPath(),
"r").getChannel();
... but this doesn't work, if resource is packed in jar file.
-Ulf
