Possibly two overloadings? One that takes a array public static int hash(Object[] values) The other* *hash(Object value1, Object value2, Object... restOfValues)
The one object case is just object.hashcode() right? On Mon, Jan 11, 2010 at 10:20 AM, Marek Kozieł <develop4l...@gmail.com>wrote: > 2010/1/10 Neal Gafter <n...@gafter.com>: > > On Sun, Jan 10, 2010 at 12:14 AM, Paulo Levi <i30...@gmail.com> wrote: > >> Just seen the new Objects class in the java.util. > >> > >> I'd like to ask why does the > >> > >> public static int hash(Object... values) > >> > >> method, has the warning: > >> Warning: When a single object reference is supplied, the returned value > does > >> not equal the hash code of that object reference. This value can be > computed > >> by calling hashCode(Object). > >> > >> When it could be rewritten as : > >> > >> public static int hash(Object value1, Object value2, Object... > restOfValues) > >> > >> to avoid that. > > > > That would make it hard to pass an array. > > > Hello. > > Name "hashForArray" would not be better? > > If there is need for efficiency improvements other methods can be > added to do not force arrays creation for low number of arguments: > > public static int hash(Object value) > public static int hash(Object value, Object value1) > public static int hash(Object value, Object value1, Object value3) > public static int hash(Object... values) > public static int hash() // maybe ? > > > But I'm not sure if we need that, probably time will tell... > > -- > Pozdrowionka. / Regards. > Lasu aka Marek Kozieł >
