On 02/28/2013 09:07 AM, Volker Simonis wrote:
Probably because the API-Spec
(http://docs.oracle.com/javase/7/docs/api/java/lang/StringBuilder.html#toString%28%29)
says "..A new String object is allocated and initialized to contain
the character sequence currently represented by this object..".
Regards,
Volker
Also, this kind of short circuit 'if' in a heavily used code like
StringBuilder.toString() can have bad interaction with the way the VM
optimize/deoptimize. See this thread for more information.
http://mail.openjdk.java.net/pipermail/core-libs-dev/2012-May/010295.html
Rémi
On Thu, Feb 28, 2013 at 8:47 AM, Jan Ohlsen <jan.t.ohl...@gmail.com> wrote:
System.out.println( new StringBuilder().toString() == "" );
-> "false"
Any reason for not returning the "" instance?
public String toString() {
return new String(value, 0, count);
}
-->
public String toString() {
return (count > 0) ? new String(value, 0, count) : "";
}
?
