Bitten again by the very same issue :(
The following code doesn't compile:
static <K, T> Function<K, T> factory(Consumer<? super BiConsumer<? super
K, ? super T>> consumer, Function<? super K, ? extends T> ifAbsent) {
HashMap<K, T> map = new HashMap<>();
consumer.accept(map::put);
return key -> map.computeIfAbsent(key, ifAbsent);
}
I really think that it's a serious bug, the only workaround is to not
use wildcards correctly, i.e.
<K, T> Function<K, T> factory(Consumer<BiConsumer<? super K, ? super
T>> consumer, Function<? super K, ? extends T> ifAbsent)
cheers,
Rémi
On 05/27/2015 05:29 PM, Remi Forax wrote:
Hi all,
The way the conversion between a lambda (or a method reference) and a
functional interface is specified doesn't take wildcard (exactly ?
super) into account making the concept of contravariance of functional
interface less intuitive that it should be.
The following code compiles:
private static void create(Consumer<Consumer<String>> consumer) {
consumer.accept(s -> System.out.println(s));
}
This one doesn't compile because "? super Consumer<? super String>" is
not a functional interface:
private static void create2(Consumer<? super Consumer<? super
String>> consumer) {
consumer.accept(s -> System.out.println(s));
}
The workaround is to introduce a cast :(
private static void create3(Consumer<? super Consumer<? super
String>> consumer) {
consumer.accept((Consumer<String>)s -> System.out.println(s));
}
which is stupid in this case because there is no ambiguity.
This cast is just here because the JLS doesn't consider that ? super
Consumer<...> is a valid target type
IMO, this bug is very similar to JDK-6964923 and i think the spec
should be changed to allow ? super Foo to be a valid target type for a
lambda conversion (obviously if Foo is a functional interface).
regards,
Rémi
