On Mon, Apr 03, 2006 at 03:02:33PM -0700, [EMAIL PROTECTED] wrote:
>
> i think process perent for each user is the same, so:
>
> ps -ef | grep -v root | grep "imapd\|pop3d" | awk '{print $3}'| sort |
> uniq | wc -l
>
> should work.
> i might be wrong though
>
Each imapd process (for example) is a son of couriertls process.
But if one user (through thunderbird for example) opens 3 connexions,
the three independant imapd processes will have 3 couriertcpd parents.
So, this doesn't give the expected result.
Thanks for your guesses, however,
Pierre David
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