[C++-sig] Class scoped enum losing scope

[Rao, Sumeeth]

Hello

I am a newbie in using boost python. I use boost python version 1.33.1, on 
linux x64 Fedora 9 2.6.26.3-29 kernel.
Here is a problem I am facing:

C++ code:
class Foo{
public:
   typedef enum {
        TYPE_A,
        TYPE_B,
        TYPE_C
    }eType;
};

class  Bar {
 public:
    bool barfun(Foo::etype type);
};


Boost Python bindings:
In foo.pypp.cpp:
void register_Foo_class(){

    { //::Foo
        typedef bp::class_< Foo > Foo_exposer_t;
        Foo_exposer_t Foo_exposer = Foo_exposer_t( "Foo" );
        bp::scope Foo_scope( Foo_exposer );
        bp::enum_< Foo::eType>("eType")
            .value("TYPE_A", Foo::TYPE_A)
            .value("TYPE_B", Foo::TYPE_B)
            .value("TYPE_C", Foo::TYPE_C)
            .export_values()
            ;
}

In bar.pypp.cpp:

struct Bar_wrapper : Bar, bp::wrapper<Bar > {
    ......

    bool barfun( ::Foo::eType eType,) {
        if( bp::override func_barfun = this->get_override( "barfun" ) )
            return func_barfun( eType);
        else
            return this->Bar::barfun( eType);
    }


    bool default_barfun( ::Foo::eType eType) {
        return Bar::barfun( eType);
    }

    .....
};

void register_Bar_class(){

    bp::class_< Bar_wrapper >( "Bar" )
      .....

        .def(
            "barfun"
            , &::Bar::barfun
            , &bar_wrapper::default_barfun
            , ( bp::arg("eType") ) )
     .....
};


>python
>>> import Boost_FooBar
>>>
>>> bar = Boost_FooBar.Bar()
>>>
>>> var = Boost_FooBar.Foo.eType.TYPE_B           < --Seems to understand that 
>>> there is a  Foo::etype::TYPE_B value
>>> var
Boost_FooBar.eType.TYPE_B               <------------------ var seems to have 
"lost" the scope of class Foo!
>>> print var
TYPE_B
>>>
>>> stat = bar.barfun(Boost_FooBar.Foo.eType.TYPE_B)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
Boost.Python.ArgumentError: Python argument types in
    Bar.barfun(Bar, Boost_FooBar.eType)                 < ------ Why is the 
parameter not of type Boost_FooBar.Foo.eType?
did not match C++ signature:
    barfun(Bar_wrapper {lvalue}, Foo::eType eType)
    barfun(Bar {lvalue}, Foo::eType eType)


Could someone help me in figuring out the problem why the class scope is being 
"lost" or the reason python is converting Boost_FooBar.Foo.eType   to 
Boost_FooBar.eType

Thanks
Sumeet



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