Hello!
I want to wrap with boost.python a C++ class "DataCube" which has overloaded
the operator=.
The constructor DataCube::DataCube(double x) allocates huge amounts of memory
and fills it with x's.
The DataCube::operator=(double x) just overwrites the already allocated memory
with x's.
Now in C++ these commands first allocate memory, which is filled with 0.'s, and
then overwrite the memory with 42.'s:
>DataCube data(0.)
>data=42.
In Python these commands first build the DataCube as desired, but then set
data=42. (now data is a float), where the reference to the DataCube is lost:
>data=DataCube(0.)
>data=42.
I have circumvented this by replacing the second line with
> data.assign(42.)
with a function assign which is defined appropriately, but I would prefer to
use the same assignment as in C++.
Finally the question:
Can I define the DataCube class in Python, so that the data variable above will
behave as in C++, when I write "data=42." ?
In other words, is there any possibility in Python that "x=y" does NOT make x a
reference to y?
Thank you
Hans
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