Try something like this:
float get_a(const Foo& self) {return self.a}
void set_a(Foo& self, float a_new) {self.a = a_new }
class_<Foo>("Foo", init<>())
.def_property("a", &get_a, &set_a)
;
-----Original Message-----
From:
cplusplus-sig-bounces+matthew.scouten=tradingtechnologies....@python.org
[mailto:cplusplus-sig-bounces+matthew.scouten=tradingtechnologies....@py
thon.org] On Behalf Of Sebastian Kraemer
Sent: Wednesday, July 22, 2009 9:57 AM
To: cplusplus-sig@python.org
Subject: Re: [C++-sig] wrapping reference members
> I would think that .def_readwrite would do what you need. If it
doesn't
> look at using .def_property and get/set pair. Caveat: making sure that
> 'a' stays a valid reference is your problem. Python will happily crash
> horribly (if you are lucky) in response to bogus pointers or
references.
Thanks for your fast answer! I tried it with following code:
class_<Foo>("Foo", init<>())
.def_readwrite("a", &Foo::a)
;
But it raises the error:
error: cannot create pointer to reference member 'Foo::a'
And it seems it's really not possible to create a pointer to a reference
in c++ ;) So what else do I have to write instead of "&Foo::a"?
Cheers,
Sebastian
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