On Tue, Dec 15, 2009 at 12:35 AM, Nikolaus Rath <nikol...@rath.org> wrote: > Roman Yakovenko <roman.yakove...@gmail.com> writes: >>> Certainly all the exported symbols should already be available from >>> parsing the header file... Is it possible to omit the symbols file >>> and generate code based only on the headers? >> >> I don't think so( it didn't worked in my use case ) but you can try. >> Start to comment out code in ctypes_builder.py and post the result :-) > > I looked into the xml file created by gccxml and (at least in the case > of C code) it seems to contain all the information that's needed. > > I modified parsers.py to return an empty dict if no symbols_file is > provided: > > def merge_information( global_ns, fname, runs_under_unittest=False ): > """high level function - select the appropriate binary file parser and > integrates > the information from the file to the declarations tree. """ > if fname is None: > return dict() > > > this seems to work partially. I can still export all the struct's, but I > no longer get any function exports. I can mark them as to be exported > without any error, but they don't show up in the generated code. > > Any idea?
Yes. Py++ thinks that those functions are "private" and doesn't export them. You should dig father ( creators_factory/ctypes_creator.py ). -- Roman Yakovenko C++ Python language binding http://www.language-binding.net/ _______________________________________________ Cplusplus-sig mailing list Cplusplus-sig@python.org http://mail.python.org/mailman/listinfo/cplusplus-sig
