On Sun, Mar 21, 2010 at 10:06 AM, Maciej Sitarz <macieksit...@wp.pl> wrote:
> Yes, it works, because there's no code generated for std::vector<item_t>
> Try adding this function to item_t class:
> void fund( std::vector<item_t>& v) { }
>
> And then it doesn't compile successfully.
>
> When I comment this line from the generated code:
> vector_less__item_t__greater__exposer.def( bp::indexing::vector_suite<
> std::vector< item_t > >() );
> it compiles and appears to work, but I can't figure out how to pass a
> list/vector to that function:
>
>
> import test
> item = test.item_t( 10 )
> vect = [test.item_t(1), test.item_t(2)]
> item.fund(vect)
> ---------------------------------------------------------------------------
> ArgumentError Traceback (most recent call last)
>
> /home/macieks/error_examples/protected_assign/<ipython console>
>
> ArgumentError: Python argument types in
> item_t.fund(item_t, list)
> did not match C++ signature:
> fund(item_t {lvalue}, std::vector<item_t, std::allocator<item_t> >
> {lvalue} v)
>
> In [5]: vect
> Out[5]:
> [<test.item_t object at 0x7f8f38899e10>,
> <test.item_t object at 0x7f8f38899d60>]
>
> In [6]: vect?
> Type: list
> Base Class: <type 'list'>
> String Form: [<test.item_t object at 0x7f8f38899e10>, <test.item_t object
> at 0x7f8f38899d60>]
> Namespace: Interactive
> Length: 2
> Docstring:
> list() -> new list
> list(sequence) -> new list initialized from sequence's items
>
> I'm not sure, but that should work, shouldn't it?
1. I would talk with developers to understand the reasons for such interface
2. create wrapper function, which takes regular python list and
creates a vector from it and expose this function, instead of the
original one
--
Roman Yakovenko
C++ Python language binding
http://www.language-binding.net/
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