Thank you very much for your suggestion.
Jean-Joseph
________________________________
De : Jim Bosch <tallji...@gmail.com>
À : christophe jean-joseph <jjchristo...@yahoo.fr>
Cc : "cplusplus-sig@python.org" <cplusplus-sig@python.org>
Envoyé le : Mercredi 21 mars 2012 17h32
Objet : Re: Re : Re : [C++-sig] Re : [boost] Re : Using an element of a class A
in a constructor of a class B (reflection with boost::python)
On 03/21/2012 12:09 PM, christophe jean-joseph wrote:
>
>
> Thank you for your answer,
>
> As I said, the solution I am currently using is working fine, I am just using
> a method explained in the tutorial for a function independant from any class:
>
> http://wiki.python.org/moin/boost.python/ExportingClasses
>
>
> and I extend it to a function of another class.
> You recommend to write things that way:
>
> class_< A_i, bp::bases<B> >(...);
>
>
> but, A_i are not derived from B, and as they are already derived from
> A_Base_j classes (some from a same base class, not all of them), I already
> declared their base classes.
> Declaring a function B::f(A& a, ...) in A as:
> .def("f",&B::f)
> keep C++ declaration (I mean, even if B::f is declared in A, it's declared as
> a method of B, which is correct).
> But what your are proposing seems not correct to me, as long as A isn't a
> derived class from B.
>
Oh, I understand now. "B::f" is a static member function that takes an "A" as
its first argument. You just want a more elegant way to wrap a lot of similar
classes.
You may not be able to get it a lot cleaner, but you can cut down some of the
boilerplate by writing a templated function to wrap an "A" class. You can then
just call that repeatedly:
template <typename T>
void wrapA(char const * name) {
bp::class_<T>(name, ...)
.def("F", &B::f)
;
}
BOOST_PYTHON_MODULE(whatever) {
wrapA<A_1>("A_1");
wrapA<A_2>("A_2");
...
wrapA<A_n>("A_n");
}
Of course, you'll have to modify it to do more than that, but hopefully that
will get you started.
Jim_______________________________________________
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