Hi,

I'm still strugling with this whole thingy so I came up with more concrete example I'm trying to achieve:

http://pastebin.com/dVRfT56x


And in python code I do like this:

owner = Owner()
data = Data(owner)

After script is finished I get warning message that Data destructor shouldn't be called directly. And then python crashes due memory corruption.

I've tried to make usage of shared_ptr but no luck and I didn't understood how to apply shared_ptr_for_this.

(NOTE: in my case all classes are from 3rd party library that I have no control over)

5.7.2012 20:44, Holger Brandsmeier kirjoitti:
Jani,

ok what you want to do is quite a lot more intrusive, so you need some
more involved methods, but it should be possible. I would do it by
noting the following
  - data_1 is published to python as a boost::shared_ptr<Data> (default
holder type)
  - usually it is difficult for a class member function, to obtain a
shared_ptr<> to itself, i.e. something like `this` but not of type
Data* but of boost::shared_ptr<Data>.
  - fortunately there is something supported by boost itself, called
`enable_shared_from_this`, see
   http://stackoverflow.com/questions/142391/getting-a-boostshared-ptr-for-this
  - Now you want `owner` to hold on to this `shared_ptr<Data>` which
ensures that `data_1` does not get deleted before `owner`, you can do
this by
   owner->setData( shared_from_this() )
in any member function of `Data`.
  - Note that I _think_ that you are not allowed to use
`shared_from_this()` in the constructor itself, so you might have to
use boost::pythons `make_constructor` to make an ordinary member /
non-member function behave as the constructor in python.

Maybe someone has a quicker way of doing this, but remember that this
is exactly the use case that `shared_ptr` are made for,
Holger


On Thu, Jul 5, 2012 at 6:47 PM, Jani Tiainen <[email protected]> wrote:
I want to do it another way around:

Instance of Owner should hold reference to data_1 and data_2 as long as
owner is alive.

Now following happens:
owner = Owner()
data_1 = Data(owner) # data_1 ownership is transferred to owner object
data_2 = Data(owner) # data_2 ownership is transferred to owner object

print owner.get_data_objects()

<data_1>, <data_2>

del data_1
del data_2

print owner.get_data_objects()
# Crash because data_1 and data_2 are deleted even owner should still hold
the reference.

I tried to do it like
http://www.boost.org/doc/libs/1_49_0/libs/python/test/injected.cpp  but it
didn't worked for me.


On Thu, Jul 5, 2012 at 7:00 PM, John Reid <[email protected]>
wrote:

On 05/07/12 11:49, Jani Tiainen wrote:
Hi,

I'm new to python.boost library and I'm trying to use it to wrap a third
party library. Everything else I've managed to get working - thanks to
excellent library and lot of examples I've found around a net.

Only thing I can't get working properly is instance ownership transfer
in constructor.

So classes in library are defined like follows:

class Owner {
...
}

class Data {
     Data(Owner *owner); // <-- Here happens ownership transfer.
}


Python code is like follows:

owner = Owner()
data_1 = Data(owner)
data_2 = Data(owner)

So when Python script stops runnning it causes crash due the fact that
I've data objects are automatically destroyed by Owner-class but Python
deletes them by using Data-class destructor (which shouldn't happen
ever).


If I understand you correctly then you want the owner object to remain
alive at least as long as data_1 and data_2? If so you could use
with_custodian_and_ward:

http://www.boost.org/doc/libs/1_49_0/libs/python/doc/v2/with_custodian_and_ward.html

For example something like the following should work:

         namespace py = boost::python;
         py::class_<
                 ...
         > my_class(
             "Data",
             "docstring.",
             py::init< Owner * >( "Constructor." )[
                 py::with_custodian_and_ward< 1, 2 >()
             ]
         );

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--
Jani Tiainen

- Well planned is half done, and a half done has been sufficient before...


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--
Jani Tiainen

- Well planned is half done and a half done has been sufficient before...


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