On 2022-01-16 12:29, Malte Dreschert wrote:
Hi Stefan,
thanks for answering and a greetings from northern Germany to Berlin :)
the struct is meant to hold color values (three floats) but the color
space can be different.
It contains three of these unions and one enum value that contains the
information which color space was used when the values were written.
The floats are either rgb or hsv.
The library is for reading a binary file and I only have these structs
and some methods I need to wrap, that means I only need to read the
values.
I guess I would first check the color space and then interpret the
three values accordingly.
Right, and I assume you already have a C++ API to access that struct,
even if it isn't in terms of member functions. As far as the raw data
type and its binary representation is concerned, there is nothing
special here, i.e. you could wrap it in a Python object as-is. But what
you likely want is a set of (member) functions to access the values, and
that is very likely mapping to your C++ API more than mapping to the
struct directly.
For example, let's assume you have:
```
struct someStruct {/*...*/};
float get_value(someStruct const &);
void set_value(someStruct &, float);
```
you may decide to map `get_value` and `set_value` to direct methods:
```
class_<someStruct> s("someStruct");
s.def("get_value", get_value);
s.def("set_value", set_value);
```
(Notice how the freestanding functions lend themselves naturally to
become methods as their first argument is the equivalent of the
otherwise implied "this" pointer...)
Or you may want to map both directly to a property:
```
class_<someStruct> s("someStruct");
s.add_property("value", get_value, set_value);
```
Either way, there is nothing special in this wrapping concerning the
fact that your struct contains a union. Rather, it's your C++ API that
will have to deal with that.
Regards (from Montreal ;-)),
Stefan
--
...ich hab' noch einen Koffer in Berlin...
null
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