In the show_member_offset() function, when trying to handle function pointers, the case for "(*" is handled. However, if the function pointer returns a pointer or a pointer to a pointer, then the condition is unhandled. This results in the offset not being printed.
Fix by first checking if the member is potentially a function pointer, then checking if it returns a pointer or a pointer to a pointer. Signed-off-by: John Pittman <[email protected]> --- symbols.c | 11 +++++++++-- 1 file changed, 9 insertions(+), 2 deletions(-) diff --git a/symbols.c b/symbols.c index a2d5c6c..5d7da6e 100644 --- a/symbols.c +++ b/symbols.c @@ -8356,8 +8356,15 @@ show_member_offset(FILE *ofp, struct datatype_member *dm, char *inbuf) } } else if (c) { for (i = 0; i < c; i++) { - if (STRNEQ(arglist[i], "(*")) { - target = arglist[i]+2; + if (strstr(inbuf, "(*")) { + if (STRNEQ(arglist[i], "(*")) + target = arglist[i]+2; + else if (STRNEQ(arglist[i], "*(*")) + target = arglist[i]+3; + else if (STRNEQ(arglist[i], "**(*")) + target = arglist[i]+4; + else + continue; if (!(t1 = strstr(target, ")"))) continue; *t1 = NULLCHAR; -- 2.17.2 -- Crash-utility mailing list [email protected] https://listman.redhat.com/mailman/listinfo/crash-utility
