"R. Hirschfeld" wrote on QKD: > The eavesdropper Eve doesn't know with which basis to measure the > polarity of the each intercepted photon. When she guesses right, she > gets the correct information and can send it on undetectably. When > she guesses wrong, she gets a zero or one with equal probability (*) > and half the time sends on the wrong bit (which is again randomized > when Bob reads it with the correct basis). By eavesdropping Eve thus > introduces a 25% error rate, which is detectable.
If I understand this correctly, this is both an eavesdropping scenario and an MITM scenario. In the above, Eve is acting as Mallory, as she is by definition intercepting the bits and re- sending them on? That is, the "Quantum Property" is that Eve can be detected because she destroys photos in the act of listening, and Mallory, who can resend the photons, has only a 50% chance of reading each bit correctly in advance, so he can be detected after the fact as well, as 25% of his bits are wrong. iang --------------------------------------------------------------------- The Cryptography Mailing List Unsubscribe by sending "unsubscribe cryptography" to [EMAIL PROTECTED]