Not really.. The google code is css3 and the w3c validator checks
for 2.1.
If you change the profile=css21 in the validator url to
profile=css3 it will
validate..
Gerhard
Yes, I tried. But it still comes back with an error.
I tested just this:
body {
font: 65%/1.4 "PT Sans" "Trebuchet MS", Arial, Helvetica, sans-serif;
background: #d9ebd5 url(images/body_bg.jpg) repeat-x;
margin: 0; padding: 0; color: #333;
}
And got this:
W3C CSS Validator results for TextArea (CSS level 3)
Sorry! We found the following errors (1)
URI : TextArea
2 body Value Error : font Too many values or values are not
recognized : 65%/1.4 "PT Sans" "Trebuchet MS",Arial,Helvetica,sans-
serif 65%/1.4 "PT Sans" "Trebuchet MS",Arial,Helvetica,sans-serif
And the Error in Firefox when I try the page says this:
Warning: Expected end of value but found '"Trebuchet MS"'. Error in
parsing value for 'font'. Declaration dropped.
Source File:
file:///Volumes/Hi%20MAC%20Too/Users/stevecaramia/Desktop/geekosystems_/geekostyles.css
Line: 3
Line 3, of course, is font: 65%/1.4 "PT Sans" "Trebuchet MS", Arial,
Helvetica, sans-serif;
Again, if I delete "PT Sans," if validates just fine. One step
forward. 3/5ths of a step back.
http://geekosystemscom.ipage.com/
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