Not really.. The google code is css3 and the w3c validator checks for 2.1. If you change the profile=css21 in the validator url to profile=css3 it will
validate..

Gerhard


Yes, I tried. But it still comes back with an error.

I tested just this:

body {
        font: 65%/1.4 "PT Sans" "Trebuchet MS", Arial, Helvetica, sans-serif;
        background: #d9ebd5 url(images/body_bg.jpg) repeat-x;
        margin: 0; padding: 0; color: #333;
}

And got this:

W3C CSS Validator results for TextArea (CSS level 3)

Sorry! We found the following errors (1)

URI : TextArea

2 body Value Error : font Too many values or values are not recognized : 65%/1.4 "PT Sans" "Trebuchet MS",Arial,Helvetica,sans- serif 65%/1.4 "PT Sans" "Trebuchet MS",Arial,Helvetica,sans-serif

And the Error in Firefox when I try the page says this:

Warning: Expected end of value but found '"Trebuchet MS"'. Error in parsing value for 'font'. Declaration dropped.
Source File: 
file:///Volumes/Hi%20MAC%20Too/Users/stevecaramia/Desktop/geekosystems_/geekostyles.css
Line: 3

Line 3, of course, is font: 65%/1.4 "PT Sans" "Trebuchet MS", Arial, Helvetica, sans-serif;

Again, if I delete "PT Sans," if validates just fine. One step forward. 3/5ths of a step back.



http://geekosystemscom.ipage.com/
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