What is different about the way i increments (or the way i's changes are
noted) in foo and bar?
Theresa
On Thu, 2011-09-29 at 23:42 -0400, Robert Citek wrote:
> Given these two functions:
>
> $ foo () { for i in {1..10} ; do { sleep $i ; } & done ; wait ; }
> $ bar () { echo {1..10} | tr ' ' '\n' | while read i ; do { sleep $i ;
> } & done ; wait ; }
>
> Why does foo take 10 seconds and bar is instant? Apparently, foo is
> actually waiting for the background processes to finish, whereas bar
> is not. Why not? And how can I get bar to act like foo, i.e. wait
> for bg processes to finish)?
>
> $ time -p foo 2> /dev/null
> real 10.01
> user 0.18
> sys 0.03
>
> $ time -p bar 2> /dev/null
> real 0.00
> user 0.02
> sys 0.00
>
> Regards,
> - Robert
>
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