At 09:05 PM 8/18/2003 -0400, Christopher Faylor wrote: >Nevermind. It doesn't work the way I remembered. The while loop which >decrements sigtodo only executes once when it encounters a normal UNIX >signal (it probably should just be recoded as an if). So, this should >be a non-issue. In fact, I don't see how multiple signals coming in at >the same time would have the effect you mentioned either. > I don't understand. The sigtodo of a signal is decremented once but the code immediately continues in the for loop for the next signal. Two signals can be processed during a cycle of the outside for (;;) and they will have the same rc.
Pierre
