As requested the output from perl -e "print $^X;" Bash 3 => c:\opt\perl\bin\perl.exe
Bash 4 => /usr/bin/perl As you would expect the program that is actually running. But again Bash 4 is incorrectly getting /usr/bin/perl rather than /opt/perl/bin/perl -----Original Message----- From: Csaba Raduly [mailto:rcs...@gmail.com] Sent: 30 December 2009 08:52 To: cygwin@cygwin.com; neil.mowb...@calgacus.com Subject: Re: Bash v4.0 does not respect $PATH On Tue, Dec 29, 2009 at 11:21 PM, Neil Mowbray wrote: > Folks, > > I need associative arrays so I got the bash 4.0 source, compiled it > under cygwin and installed it in /usr/local/bin. > > I have ActiveState perl installed in /opt/perl which preceeds > /usr/local/bin:/bin:/usr/bin on my path. Using bash 4.0, 'which' says > I should get ActiveState perl, but actual execution gives cygwin perl > in /bin Are you sure PATH is the same in bash 3 and 4? You only showed the PATH from bash 4. Just out of curiosity, what does perl -e 'print $^X' print in those two situations? Also, try running for i in $(echo $PATH | sed -r -e "s/:/ /g"); do ls -l $i/perl; done in both shells. -- Life is complex, with real and imaginary parts -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
