> -----Original Message-----
> From: Magnus Holmgren [mailto:[EMAIL PROTECTED]]
> Sent: Monday, January 13, 2003 7:51 PM
> To: [EMAIL PROTECTED]
> Subject: Tab completion list takes enormously long time to generate from
> empty string
> 
> 
> Greetings.
> 
> When I press tab in bash without having typed anything at all 
> (which is somewhat abusive but it easily happens), bash works for 
> 15 minutes, going through $PATH looking for executables (and in 
> the end producing nothing) on a 2x450 MHz PIII. Is that normal?
> 
> My $PATH contains the usual /usr/local/bin:/usr/bin:/bin, the 
> WINNT and System32 directories, plus some relatively neglectable 
> ones (18 directories in total), but the number of directories in 
> the path and the time it takes to go through their contents is 
> not the problem. Matching an executable in the last directory in 
> $PATH only takes about 0.2 s. Instead, the huge size of the 
> resulting list seems to be what causes the delay, especially when 
> considering that no disk I/O at all is performed during 14 min 59 
> sec of the 15 minutes...
> 
> I suspect that someone has chosen a sorting algorithm with time 
> complexity O(N^2). Or O(2^N)...
> 
> Maybe I can find that out myself.
> 
> Cheers,
> Magnus
> 
Correction; there is no writing to disk, but certainly loads of *reading*, and 
quicksort seems to be used, so I don't blame the sorting anymore.

I reckon that all files in $PATH (except .exe-s) have to be opened to see if they 
start with #!, and that that takes some time. Getting rid of some entries in $PATH 
surely reduces the time consumed, but I still think that more than five seconds is too 
much.

Some optimizations should be possible, such as only checking files with certain 
extensions, like .sh, .pl, and none at all for the magic "#!" or caching the list in 
some form. A second option might even be to disallow tab completion of commands 
without entering a prefix.

/Magnus


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