I have a habit of keeping cygwin packages on my computer and updating them from time to time using setup.exe. This saves me time when I need to install on another computer.
This creates a problem of old versions of packages accumulating in my download directory. I used to remove them by hand but that is a time consuming process. Finally I wrote an awk script to help me deal with the problem. And just for kicks I added a shell wrapper :).
Attached are the scripts. I hope they could be useful to someone else. I am sure they can be improved but they have been useful to me as is.
Thanks, Alex
#! /bin/awk BEGIN { \ last_pkg = ""; last_date = 0; last_dir = ""; last_pkg_name = ""; cmd = "find release -type f -printf '%h %f %TY%Tm%Td\n'"; while(( cmd | getline ) > 0) { dir = $1; pkg = $2; date = $3; count = split(dir, part, "/"); if( last_pkg_name == part[count] ){ if( date < last_date ){ print dir "/" pkg; continue; }else{ print last_dir "/" last_pkg; } } last_pkg = pkg; last_date = date; last_dir = dir; last_pkg_name = part[count]; } close(cmd); }
#! /bin/bash # Version of cyg-remove-dups in bash, just for kicks. Still uses awk and find # awk is used in a normal way. Trick is to pass program to it with the data # on stdin. find release -type f -printf "%h %f %TY%Tm%Td\n" | \ awk -- ' BEGIN { \ last_pkg = ""; last_date = 0; last_dir = ""; last_pkg_name = ""; } { dir = $1; pkg = $2; date = $3; count = split(dir, part, "/"); if( last_pkg_name == part[count] ){ if( date < last_date ){ print dir "/" pkg; next; }else{ print last_dir "/" last_pkg; } } last_pkg = pkg; last_date = date; last_dir = dir; last_pkg_name = part[count]; } '
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