I've upgraded my cygwin and bash yesterday.

I'm puzzled by what I see and every attempt I've made at generating a
smaller test case has failed.

Anyway, one script prints a message that it's about to call another
script. On return from the script, another message is printed. The called
script notices certain files are not present, then prints a message to
that effect and exits with an error code.

But, the message 2nd message on the calling script never prints and I'm
just stumped. All I can think is that bash is unaware that the script
exited or terminated.

A portion of the calling script: uptime2xls

echo "$me($$): `date` start rtf2uptime"
rtf2uptime
#raw24csv2xls
echo "$me($$): `date` remove any left over raw24 csv files"

A portion of the rtf2uptime script:

FILES="`ls *rtf 2>/dev/null`"
if [ -z "$FILES" ]; then
    echo "No .rtf files found"
    exit 1
fi

The output I see:

uptime2xls(2120): Fri Jul  8 09:39:19 EDT 2005 start rtf2uptime
No .rtf files found

Note that the "remove any left over raw24 ..." message does not print.


--
Ken Shaffer



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