<snip> > "i=i++" is either a no-op or nonsense, depending on the > interpretation. You should either use "i=i+1" or "i++" (those should > be equivalent in modern compilers).
The strick interpretation of i=i++ starts by evaluating the right side "i++" to compute a r-value (right value). Since the ++ is after the i, it is a post-operation, vs. if it were before the i, in which case it would be a pre-operation. So first the value of i would be saved, then i incremented, then the saved value would be assigned to the l-value (left value) which in this case is i, setting i back to its original value. You could use "i=++i" which would increment i, then save the r- value and assign to the l-value, but then again, i++ would be much simplier, no? Brett ---------------------------------------------------------------- Brett C. Serkez, Techie -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/