Any response?
TIA
--- Martin <[EMAIL PROTECTED]> wrote:
> I am attempting to invoke a command with
> execvp/execlp. If a file appears in my PATH before
> the executable desired and has the same name as the
> executable, the first occurrence of the file name is
> used as the executable to invoke. Even though the
> first file is NOT marked as executable.
>
> The attached testcase illustrates this.
> Here's a simple shell log:
>
> bash-3.00$ gcc test2.c -o test2
> bash-3.00$ PATH=/usr/bin:.
> bash-3.00$ test2 nopathnoext
> NoPathNoExt
> bash-3.00$ touch echo
> bash-3.00$ ls -l echo
> -rw-r--r-- 1 test None 0 Jan 21 15:39 echo
> bash-3.00$ test2 nopathnoext
> NoPathNoExt
> bash-3.00$ PATH=.:/usr/bin
> bash-3.00$ test2 nopathnoext
> nopathnoext: No such device or address
> bash-3.00$ rm -f echo
> bash-3.00$ test2 nopathnoext
> NoPathNoExt
> bash-3.00$ echo garbage > echo
> bash-3.00$ test2 nopathnoext
> nopathnoext: Permission denied
> bash-3.00$ ls -l echo
> -rw-r--r-- 1 test None 8 Jan 21 15:40 echo
> bash-3.00$ test2 nopathext
> NoPathExt
> bash-3.00$ test2 path
> Path
>
> Is this normal behavior for execlp/execvp?
> Shouldn't the execution permission be set in order to
> execute it?
>
> Thanks for your help,
> Martin
>
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